Cellulose Acetate막(膜) 전기영동법(電氣泳動法)에 의한 종모우(種牡牛)의 혈청단백분획(血淸蛋白分劃)에 관한 조사(調査)

• Lee, Chang-Woo (College of Veterinary Medicine, Seoul National University)
• 이창우 (서울대학교 수의과대학)
• Published : 1982.10.09

Abstract

Total protein levels of 60 bovine bull sera were treasured with refractometer and the strum proteins were fractionated by cellulose acetate membrane electorphoresis and the relative amount of each fraction was measured with automatic scanning densitometer. The sixty bovine bulls consisted of 17 Charolais bulls, 28 Holstein bulls and 15 Korean bulls. Mean total serum protein level of the total bulls was $7.50{\pm}0.50(Mean{\pm}SD)$, with the mean of Charolais $7.04{\pm}0.37g/dl$, the mean of Holstein $7.62{\pm}0.40g/dl$ and the mean of Korean $7.81{\pm}0.43g/dl$. As barbital-calcium buffer was used in fractionating the bovine serum protein with cellulose acetate membrane, electric current of 0.4 mA per centimeter width of the membrane for an hour resulted in more clear separation between ${\alpha}_1$-globulin and ${\alpha}_2$-globulin than electric current of 0.6 or 1.0 mA for an hour. However ${\alpha}_1$-globulin and ${\alpha}_2$-globulin could not be measured separately with automatic scanning densitometer. Mean serum albumin level of total bulls was $3.54{\pm}0.42g/dl$, with the mean of Charolais $3.42{\pm}0.26g/dl$, the mean of Holstein $3.69{\pm}0.38g/dl$ and the mean of Korean $3.39{\pm}0.55g/dl$. Mean serum ${\alpha}$-globulin level of the total bulls was $0.62{\pm}0.14g/dl$, with the mean of Charolais $0.61{\pm}0.07g/dl$, the mean of Holstein $0.60{\pm}0.11g/dl$ and the mean of Korean $0.67{\pm}0.23g/dl$. Mean ${\beta}$-globulin level of the total bulls was $0.85{\pm}0.21g/dl$, with the mean of Charolais $0.74{\pm}0.11g/dl$, the mean of Holstein $0.83{\pm}0.14g/dl$ and the mean of Korean $1.02{\pm}0.30g/dl$. Mean serum ${\gamma}$-globulin level of the total bulls was $2.48{\pm}0.45g/dl$ with the mean of Charolais $2.27{\pm}0.37g/dl$, the mean of Holstein $2.48{\pm}0.44g/dl$ and the mean of Korean $2.72{\pm}0.47g/dl$.