• 제목/요약/키워드: M%25C3%25B6ssbauer spectroscopy

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Crystallographic and Magnetic Properties of Li0.7Co0.2Ti0.2V0.2Fe1.7O4 Ferrite

  • Chae, Kwang-Pyo;Kwon, Woo-Hyun;Lee, Jae-Gwang
    • Journal of Magnetics
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    • 제15권1호
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    • pp.25-28
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    • 2010
  • This study examined the crystallographic and magnetic properties of vanadium-substituted lithium cobalt titanium ferrite, $Li_{0.7}Co_{0.2}Ti_{0.2}V_{0.2}Fe_{1.7}O_4$. Ferrite was synthesized using a conventional ceramic method. The samples annealed below $1040^{\circ}C$ showed X-ray diffraction peaks for spinel and other phases. However, the sample annealed above $1040^{\circ}C$ showed a single spinel phase. The lattice constant of the sample was $8.351\;{\AA}$, which was relatively unaffected by vanadium-substitution. The average grain size after vanadium-substitution was $13.90\;{\mu}m$, as determined by scanning electron microscopy. The M$\ddot{o}$ssbauer spectrum could be fitted to two Zeeman sextets, which is the typical spinel ferrite spectra of $Fe^{3+}$ with A and B sites, and one doublet. From the absorption area ratio of the M$\ddot{o}$ssbauer spectrum, the cation distribution was found to be ($Co_{0.2}V_{0.2}Fe_{0.6})[Li_{0.7}Ti_{0.2}Fe_{1.1}]O_4$. Vibrating sample magnetometry revealed a saturation magnetization and coercivity of 36.9 emu/g and 88.6 Oe, respectively, which were decreased by vanadium-substitution.

KFeO2 분말의 제조 및 뫼스바우어 분광학 연구 (Crystallographic and Magnetic Properties of KFeO2)

  • 문승제;심인보;김철성
    • 한국자기학회지
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    • 제17권1호
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    • pp.38-42
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    • 2007
  • 단일상의 $KFeO_2$ 분말을 ball-mill법을 이용하여 제조 하였다. 결정학적 및 자기적 성질을 x-선 회절법, 중성자 회절 실험, 뫼스바우어 분광법으로 연구 하였다. x-선 및 중성자 회절실험 분석 결과 $KFeO_2$ 시료의 결정구조는 격자상수 $a_0=5.557{\AA},\;b_0=11.227{\AA},\;c_0=15.890{\AA}$을 갖는 단일상의 orthorhombic구조로 분석 되었다. 또한 시간변화에 따른 $KFeO_2$의 강한 흡습성으로 인한 급격한 변화를 확인할 수 있었다. 뫼스바우어 스펙드럼 결과 1 set(6-line)으로 분석되었다. 극저온(4.2 K)과 상온에서의 초미세자기장값(hyperfine field)은 각각 519, 489 kOe이었으며, 이성질체 이동치(isomer shift)는 0.19, 0.05 mm/s로 나타났다. $KFeO_2$의 스핀과 여기에 의한 T/Tc<0.7 이하의 초미세자기장 $H_{hf}(T)$의 변화는 $[H_{hf}(T)-H_{hf}(0)]/H_{hf}(0)=-0.16(T/Tc)^{3/2}-0.25(T/Tc)^{5/2}$로 얻어졌다.